Magnetic field strength H of a circular “thin” solenoid along its axis | |
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$$ H(t,x) = \frac{I(t) · N}{2·L}· \left( \frac{L + 2·x}{\sqrt{ d^2 + (L+2·x)^2}} + \frac{L - 2·x}{\sqrt{ d^2 + (L-2·x)^2}} \right) $$ | (A/m) |
where: $I(t)$ - current (A) at time $t$ (s), $N$ - total number of turns (unitless), $L$ - length of the solenoid (m), $d \approx D$ - diameter of the solenoid (m), $x$ - location (m) from the centre of the solenoid (the centre is located at the point x = 0) |
^{S. Zurek, E-Magnetica.pl, CC-BY-4.0}
Notes: This equation is valid only for uniformly wound solenoid, with infinitely thin wire. The instantaneous values of H are directly proportional to the instantaneous values of I. The value of B(μ_{0}) is for vacuum.