User Tools

Site Tools


calculator:solenoid_thin

Calculator of H along axis of round "thin" solenoid

Magnetic field strength H of a circular “thin” solenoid along its axis
$$ H(t,x) = \frac{I(t) · N}{2·L}· \left( \frac{L + 2·x}{\sqrt{ d^2 + (L+2·x)^2}} + \frac{L - 2·x}{\sqrt{ d^2 + (L-2·x)^2}} \right) $$ (A/m)
where: $I(t)$ - current (A) at time $t$ (s), $N$ - total number of turns (unitless), $L$ - length of the solenoid (m), $d \approx D$ - diameter of the solenoid (m), $x$ - location (m) from the centre of the solenoid (the centre is located at the point x = 0)
“Thin” solenoid ($d \approx D$) with a circular cross-section
Current I =      Diameter d = D =

Length L =      Number of turns N = (unitless)

Position on axis x =

       H (A/m) =

Notes: This equation is valid only for uniformly wound solenoid, with infinitely thin wire. The instantaneous values of H are directly proportional to the instantaneous values of I.

calculator/solenoid_thin.txt · Last modified: 2022/01/21 00:12 by stan_zurek

Disclaimer: This website is provided only for educational purposes. In no event the providers can be held liable to any party for direct, indirect, special, incidental, or consequential damages arising out of the use of this information.
Privacy and cookie policy (GDPR, etc.)